-265=-16t^2+92t

Solution for -265=-16t^2+92t equation:

-265=-16t^2+92t

We move all terms to the left:

-265-(-16t^2+92t)=0

We get rid of parentheses

16t^2-92t-265=0

a = 16; b = -92; c = -265;
Δ = b2-4ac
Δ = -922-4·16·(-265)
Δ = 25424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{25424}=\sqrt{16*1589}=\sqrt{16}*\sqrt{1589}=4\sqrt{1589}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-4\sqrt{1589}}{2*16}=\frac{92-4\sqrt{1589}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+4\sqrt{1589}}{2*16}=\frac{92+4\sqrt{1589}}{32}
$